求解力学问题中轴承的反作用力
FR=4*4=16KN
FX=0
FY=0，-FNA+FBY-FR+FNC=FBY+FNC-22=0
MB(F)=0，MB(F)= FNA * 2-ME-FR * 2+FNC * 4 = FNC * 4-30 = 0
FNC = 7.5千牛顿FBY = 14.5千牛顿
FX=0
FY=0，-FNA+FBY-FR+FNC=FBY+FNC-22=0
MB(F)=0，MB(F)= FNA * 2-ME-FR * 2+FNC * 4 = FNC * 4-30 = 0
FNC = 7.5千牛顿FBY = 14.5千牛顿