三角函数往期真题及答案 解:sin (π/4-α) = sin (π/2-π/4-α)。=sin[π/2-(π/4+α)]。=cos(π/4+α)。=√[1-sin^2(π/4+α)].=-2√2/3(∵α& gt;π/2∴cos(π/4+α)<;0.)