初中数学代数题

无论是y=kx+k-1还是y=(k+1)x+k,先表示两条直线的交点C(-1,-1),与x轴的交点是a(?1-K/K?0),B(-K/K+1,0),基数AB的长度=(1-K/K)-(-K/K+1)= 1/K(1+)s 1+S2+...+s 2006 = 1/2X(1/1x 2+1/2 x3+1/3 x4...+1/2006 x2007)= 1/2X(1-1/2+1/2-1/3+1/3-1/4+.....+1/2006-1/2007)= 1/2X(1-1/2007)= 1/2X 2006/2007 = 1003/2007