Fce真题4
ADF类似于ECF。
ADF面积=1/2 AD*DF
ECF地区=1/2 CE*CF
CE:AD=CF:(CD-CF)
CE=AD*CF/(CD-CF)
1/2 AD *(CD-CF)-1/2 CE * CF = 4
解是CE = 9,DF/CF=8/9,DF+CF= 17/9 CF = 8。
CF=72/17
DF= 64/17
AD*DF = 8 * 64/17
CE*CF = 9*72/17
CE * CF-AD * DF =(9 * 72-8 * 64)/17 = 8