数学问题3+33+333+...+333 ...333 (1000) =?
3+33+333+...+333 ...333 (1000)
= (9+99+999+...+999 ...999 (1000))/3
= (10-1+100-1+0000-1+...+1000 ...000 (1000个零)
= (111 ...11110 (1000 1)-1000) /3
= 111...1110110 / 3
999 1
= 370370...370(332 370) 3370-3370 = 10110/3
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