93第4道真题

不考虑相应的顺序，形式是:

(A + B + C)/3 + D = 93

(A + B + D)/3 + C = 135

(A + C + D)/3 + B = 75

(b+ C+D)/3+A = 111

那么如果以上四个公式加在一起，就有:

(3A+3B+3C+3D)/3+(A+B+C+D)= 414

解决方法是A+B+C+D = 207。

(A + B + C + D)/3 = 69

最初的四个数字是:

(93 - 69)÷(2/3) = 36

(135 - 69)÷(2/3) = 99

(75 - 69)÷(2/3) = 9

(111 - 69)÷(2/3) = 63