初中数学几何问题

证明:(1)≈∠DCF+∠ECB = 90，∠ DCF+∠ CDF = 90 ∴ ∠ ECB = ∠ CDF且∠∞。当n=2时，可以得到AB=2BE=BC，DF/FC=BC/BE=2。(2)当n=3，AB=2BE=BC，且DF/FC=BC/BE=3，且∵∠GFC+∠dfg =∠dfg+∠afg = 90°∴∠GFC。Ac DC，AB in m，h.s △ AEF = (AE * FH)/2，s △ DFG = (DG * FM)/2，AE = (n-1) be，DG = (n-1) CG，FH = FM = n

∴s△AEF/s△dfg =(AE * FH)/(DG * FM)= n-1 = 2，所以n=3百度地图。